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NEET UG PHYSICS MCQ: MAGNETIC EFFECT OF CURRENT

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Application +4 | -1
A toroid having average diameter 2.5 m2.5 \mathrm{~m}, number of turns 400, current =2 A=2 \mathrm{~A} and magnetic field =10 T=10 \mathrm{~T} what will be induced magnetic field? (in amp/m\mathrm{amp/m})
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Correct option: B
1084Ï€\frac{10^8}{4 \pi}
Option B (1084π\frac{10^8}{4 \pi}) is correct because it is calculated using the formula B=μ0nIB = \mu_0 n I, where n=N/2πrn = N/2\pi r.

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