Statement-I: Equivalent weight of ${NH}_3,$ in the reaction $N_2 \rightarrow N H_3$ is $17 / 3$ while that of $N_2$ is $28 / 6.$ Statement-II: Equivalent weight $=\frac{\text { Molecular weight }}{\text { number of } e^- \text{ lost or gained/mole }}$

Both the statements are incorrect

Statement-I is correct but statement-II is incorrect

Statement-I is incorrect but statement-II is correct

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NEET UG CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Statement-I: Equivalent weight of

{NH}_3,

in the reaction

N_2 \rightarrow N H_3

17 / 3

while that of

N_2

28 / 6.

Statement-II: Equivalent weight

=\frac{\text { Molecular weight }}{\text { number of } e^- \text{ lost or gained/mole }}

View answer and explanation

Correct option: A

Both the statements are correct

Option A (Both the statements are correct) is correct because the equivalent weight is calculated correctly in statement I, and statement II provides the correct definition of equivalent weight.

NEET UG CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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