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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy
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Application +4 | -1
If y=3[x]+1=2[x−3]+5y=3[x]+1=2[x-3]+5, then find the value of [x+y][x+y].
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Correct option: D
-7
Option D (-7) is correct because solving the equation 3[x]+1=2[x−3]+53[x]+1=2[x-3]+5 yields [x]=−2[x] = -2, and then y=−5y = -5, so [x+y]=[−2−5]=−7[x+y] = [-2 - 5] = -7.

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