The trajectories orthogonal to $(2 a-x) y^2=x^3$ is

$x^2+y^2=C\left(y^2+2 x^2\right)$

$\left(x^2+y^2\right)=x^3+x y^2$

JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

1 of 1

Application +4 | -1

The trajectories orthogonal to

(2 a-x) y^2=x^3

View answer and explanation

Correct option: C

\left(x^2+y^2\right)^2=C\left(y^2+2 x^2\right)

Option C (

\left(x^2+y^2\right)^2=C\left(y^2+2 x^2\right)

) is correct because it represents the orthogonal trajectories to the given family of curves.

Practice All Chapter MCQs →

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y=y(t)

\frac{d y}{d t}+\alpha y=\gamma e^{-\beta t}

\alpha>0, \beta>0

\gamma>0

\lim \limits_{{x \rightarrow \infty}} y(t)