JEE MATHEMATICS MCQ: STRAIGHT LINES

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Analyzing +4 | -1

From a common point on the lines

x y-3 y-4 x+12=0

mutually perpendicular lines

L_1

and

L_2

are drawn such that they intercept triangles of equal area with coordinate axes. If

\theta_1

and

\theta_2

are inclination of

L_1

and

L_2

with coordinate axes, then

\left|\theta_1+\theta_2\right|

is equal to

View answer and explanation

Correct option: B

\tan ^{-1}\left(\frac{24}{7}\right)

The correct answer is B (

\tan^{-1}(\frac{24}{7})

) because it is found by using the condition that the triangles have equal area and the lines are perpendicular.

More Questions from STRAIGHT LINES

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x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0