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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Application +4 | -1
The dipole moment of HBr{HBr} is 2.60×10−30 cm2.60 \times 10^{-30} {~cm} and the interatomic spacing is 1.41A∘1.41 \mathop {\text{A}}\limits^ \circ. What is the percent ionic character of HBr{HBr} ?
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Correct option: B
11.5%11.5 \%
Option B (11.5 %) is correct because the percent ionic character is calculated by dividing the observed dipole moment by the calculated dipole moment and multiplying by 100.

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