NEET UG PHYSICS MCQ: GRAVITATION

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A particle of mass m is moving in a horizontal circle of radius r,under a centripetal force

= \frac{k}{{{r^2}'}}\;\mathrm{where\;}k\mathrm{\;is\;a\;constant}.

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Correct option: A

The potential energy of the particle is zero

The potential energy is usually defined to be zero at infinity, and since the force is centripetal, it's directed towards the center, and we are not given any information to calculate the potential energy, so Option A (The potential energy of the particle is zero) is the most appropriate.

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If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force

\left( { - K/{r^2}} \right)

the total energy is Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e.

F \propto \frac{1}{r^3}

, but still remaining a central force. Then Two satellites A and B go round a planet P is circular orbits having radii 16 R and 2 R respectively. If the speed of satellite A is

6\,m{s^{ - 1}}

the speed of the satellite B will be [in m/s] nearly The total energy of satellite moving with an orbital velocity

v

around the earth is Two satellites of same mass are launched in the same orbit of radius

r

around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after collision is Statement-1: There is almost no effect of rotation of earth at poles.
Statement-2: Because rotation of earth is about polar axis.