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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
If aa is fixed real number such that f(a−x)  +  f(a+x)=0f\left( {a - x} \right)\,\, + \,\,f\left( {a + x} \right) = 0, then ∫02a  f(x)  dx=\int \limits_0^{2a} \,\,f\left( x \right)\,\,dx =
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Correct option: B
0\mathrm{0}
Option B (0) is correct because the integral of the function over the interval [0, 2a] is zero due to the property f(a−x)+f(a+x)=0f(a-x) + f(a+x) = 0, which implies f(2a−x)=−f(x)f(2a-x) = -f(x).

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