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NEET UG CHEMISTRY MCQ: BIOMOLECULES

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The optical rotation of α−D\alpha-\mathrm{D} fructose is −21∘-21^{\circ} and that of its β\beta-form is −133∘-133^{\circ}. The equilibrium mixture of these anomers has an optical rotation of −92∘-92^{\circ}. What is the %\% of α\alpha-form (upto one decimal place) in its equilibrium mixture?
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Correct option: A
36.6
Option A (36.6) is correct because the percentage of the alpha form can be calculated using the weighted average of the specific rotations of the alpha and beta forms.

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