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NEET UG PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1
A light spring of force constant 8Nm−18 \mathrm{Nm}^{-1} is cut into two equal halves and the two are connected in parallel; the equivalent force constant of the system is
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Correct option: B
32Nm−132 \mathrm{Nm}^{-1}
Option B (32Nm−132 \mathrm{Nm}^{-1}) is correct because when a spring is cut in half, the spring constant doubles, and for parallel springs, the equivalent spring constant is the sum of individual spring constants.

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