JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

The dimensions of gravitational constant G and the moment of inertia are respectively

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Correct option: B

\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^3}{\mathrm{T}^{ - 2}}} \right];\left[ {\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^0}} \right]

The correct answer is B ([

{\mathrm{M}^{ - 1}}{\mathrm{L}^3}{\mathrm{T}^{ - 2}}

];[

{\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^0}}

]) because it correctly identifies the dimensions of the gravitational constant and moment of inertia.

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\sqrt{\frac{\text { Modulus of elasticity }}{\text { Density }}}

\mathrm{ms}^{-1} \text {. }

\frac{1}{\left(\sqrt{\varepsilon_0 \mu_0}\right) t} \text {. }

\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

{\Delta t}