JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Easy

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Application +4 | -1

The energies of the electron in a hydrogen like ion are given by :

E_n=-\left(2.18 \times 10^{-18}\right) Z^2\left(\frac{1}{n^2}\right)

, where

n

is principal quantum number and

Z

is the atomic number of the element. The ionisation energy (in

\mathrm{kJ} \mathrm{mol}^{-1}

) of the

\mathrm{Li}^{2+}

ion is:

View answer and explanation

Correct option: D

11.8 \times 10^3

The correct answer is

11.8 \times 10^3

because it is calculated using the given formula for ionization energy with Z=3 and n=1, then converting to kJ/mol.

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