JEE PHYSICS MCQ: ATOMS

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Calculate the period of revolution of an electron revolving in the first orbit of hydrogen atom. Given radius of first orbit

=0.53 \mathop {\text{A}}\limits^ \circ

and

c=3 \times 10^8 \mathrm{~ms}^{-1}

View answer and explanation

Correct option: A

1.52 \times 10^{-16} \mathrm{~s}

Option A (

1.52 \times 10^{-16} \mathrm{~s}

) is correct because it is the period calculated using the formula

T = \frac{2 \pi r}{v}

with the given radius and calculated velocity.

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n

=2

{n}=1

\lambda_0

\lambda_0

{R_H} = 1.097\,\, \times \,\,{10^7}\,\,m