JEE CHEMISTRY MCQ: SURFACE CHEMISTRY

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Freundlich equation for adsorption of gases (in amount of X g) on a solid(in amount of m g)at constant temperature can be expressed as

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Correct option: B

\log \frac{X}{m} = \log k + \frac{1}{n}\log p

Option B (

\log \frac{X}{m} = \log k + \frac{1}{n}\log p

) is correct because the Freundlich adsorption isotherm is expressed as

\frac{X}{m} = k{p^{1/n}}

, which can be written in logarithmic form as

\log \frac{X}{m} = \log k + \frac{1}{n}\log p

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