JEE MATHEMATICS MCQ: CIRCLES

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Analyzing +4 | -1

If three distinct point

A, B, C

are given in the 2-dimensional coordinate plane such that the ratio of the distance of each one of them from the point

(1,0)

to the distance from

(-1,0)

is equal to

\frac{1}{2}

, then the circumcentre of the triangle

A B C

is at the point:

View answer and explanation

Correct option: B

(5 / 3,0)

Option B (

(5 / 3,0)

) is correct because it represents the circumcenter of the triangle formed by points satisfying the given distance ratio condition.

More Questions from CIRCLES

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{\left( {{\alpha ^2}{x^2} - 2\alpha \mathrm{ }x + 1} \right)^{51}},

x

\left( {\alpha ,2{\alpha ^2}} \right)

{x^2} + {y^2} = 4,

{x^2} + {y^2} - 2x + 4y - 4 = 0

{x^2} + {y^2} = {a^2}

\left( {{x_1},{y_1}} \right)

\quad \alpha, \beta

\gamma

P, Q

x^2+y^2=1

A

(-1,0)

A P, A Q

A R

G P

\cos \alpha / 2, \cos \beta / 2

\cos \gamma / 2

x+y=6

x+2 y=4

x+y=5

x-y=1

9 \pi