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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If x(y+zβˆ’x)log⁑x=y(z+xβˆ’y)log⁑y=z(x+yβˆ’z)log⁑z\frac{x(y+z-x)}{\log x}=\frac{y(z+x-y)}{\log y}=\frac{z(x+y-z)}{\log z}, then xy yx=zy yzx^y \,y^x=z^y \,y^z is equal to
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Correct option: A
zxxzz^x x^z
Option A (zxxzz^x x^z) is correct because, under the given condition, xyβ‹…yx=zyβ‹…yz=zxβ‹…xzx^y \cdot y^x = z^y \cdot y^z = z^x \cdot x^z.

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