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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
Let f(x)f(x) be a function satisfying f(x)+f(π−x)=π2f(x)+f(\pi-x)=\pi^{2}, ∀ x∈R\forall \, x \in \mathbb{R}. Then ∫0πf(x)sin⁡xdx\int\limits_{{0}}^{\pi} f(x) \sin x d x is equal to
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Correct option: C
π2\pi^{2}
The correct answer is C (π2\pi^{2}) because using the property of definite integrals and the given functional equation, the integral simplifies to π2\pi^{2} after substitution and simplification.

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