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JEE CHEMISTRY MCQ: THERMODYNAMICS
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3.0 moles of an ideal gas is heated at constant pressure from to . The work done by the gas in this expansion is:
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Correct option: A
Option A (-2.494 kJ) is correct because the work done by the gas at constant pressure is calculated using w = -nRΔT, resulting in a negative value as the gas expands.
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