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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1
The electronic configurations of four elements L,P,Q and R are given below, L=1s2,2s22p4      Q=1s2,2s22p6,3s23p5L = 1{s^2},2{s^2}2{p^4}\;\;\;Q = 1{s^2},2{s^2}2{p^6},3{s^2}3{p^5} , P=1s2,2s22p6,3s1      R=1s2,2s22p6,3s2P = 1{s^2},2{s^2}2{p^6},3{s^1}\;\;\;R = 1{s^2},2{s^2}2{p^6},3{s^2} , The formula of the ionic compounds that can be formed between these elements are:
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Correct option: C
P2L,  RL,  PQ,  RQ2{P_2}L,\;RL,\;PQ,\;R{Q_2}
Option C (P2L,  RL,  PQ,  RQ2{P_2}L,\;RL,\;PQ,\;R{Q_2}) is correct because it represents the correct ionic formulas based on the valencies of the elements L, P, Q, and R.

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