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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Application +4 | -1
The value of lim⁡x→∞xcos⁡(π4x)sin⁡(π4x)\lim\limits_{x \to \infty } x\cos \left( {\frac{\pi }{{4x}}} \right)\sin \left( {\frac{\pi }{{4x}}} \right), is
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Correct option: B
π4\frac{\pi }{4}
Option B (π4\frac{\pi }{4}) is correct because by using the identity 2sin⁡xcos⁡x=sin⁡2x2\sin x \cos x = \sin 2x and the limit lim⁡x→0sin⁡xx=1\lim_{x \to 0} \frac{{\sin x}}{x} = 1, the given limit simplifies to π4\frac{\pi }{4}.

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