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NEET UG PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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Application +4 | -1
The x and y coordinates of a particle at any time tt are given by x=8t2+5t3x = 8{t^2} + 5{t^3} and y=2ty = 2t. Where x and y are in metre and tt in seconds. The acceleration of particle at t=5t = 5 sec is
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Correct option: D
166 m/s2166\,m/{s^2}
Option D (166 m/s2166\,m/{s^2}) is correct because it is the magnitude of the acceleration vector calculated by finding the second derivatives of the x and y coordinates with respect to time and evaluating at t=5s.

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