NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

1 Hard

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Understanding +4 | -1

In an octahedral geometry, the pair of

{d}

orbitals involved in

{d}^2 {sp}^3

hybridization is:

View answer and explanation

Correct option: A

{d}_{{x}^2-{y}^2}, {~d}_{{z}^2}

The correct answer is A (

{d}_{{x}^2-{y}^2}, {~d}_{{z}^2}

). In

{d}^2 {sp}^3

hybridization, the

{d}

orbitals involved are

{d}_{{x}^2-{y}^2}

and

{d}_{{z}^2}

because they point directly along the axes.

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