JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

1 Easy

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Analyzing +4 | -1

p, q

and

r

are three propositions, then which of the following combination of truth values of

p, q

and

r

makes the logical expression

\{(p \vee q) \wedge((\sim p) \vee r)\} \rightarrow((\sim q) \vee r)

false ?

View answer and explanation

Correct option: A

p=F, q=T, r=F

Option A (

p=F, q=T, r=F

) is the correct answer because it makes the given logical expression false.

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p:A

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\sqrt{3}

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{F_1}(A,\,B,\,C) = \left( {A \wedge \sim B} \right) \vee \left[ { \sim C \wedge \left( {A \vee B} \right)} \right] \vee \sim A

{F_2}(A,\,B) = \left( {A \vee B} \right) \vee (B \to \, \sim \,A)

p

n

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n

p \Leftrightarrow q