JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

Let

f: R \rightarrow R

be a function defined by

f(x)=\left\{\begin{array}{r}{[x], x \leq 2} \\ 0, x > 2\end{array}\right.

, where

[x]

is the greatest integer less than or equal to

x

. If

I=\int\limits_{{-1}}^2 \frac{x f\left(x^2\right)}{2+f(x+1)} d x

, then the value, is

View answer and explanation

Correct option: A

\frac{1}{4}

Option A (

\frac{1}{4}

) is correct because the integral is evaluated by splitting the integration range and using the definition of the greatest integer function.

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