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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Angular momentum of an electron in an orbital is given by

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Correct option: B

\frac{h}{{2\pi }} \times \sqrt {l\left( {l + 1} \right)}

Option B (

\frac{h}{{2\pi }} \times \sqrt {l\left( {l + 1} \right)}

) is correct because the angular momentum of an electron in an orbital is given by the formula

\sqrt{l(l+1)} \frac{h}{2\pi}

.

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