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JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1
Calculate zz for the following case.
z=(x−2.5y+w)z=(x-2.5 y+w) for x=(4.72±0.12)m,y=(4.4±0.2)m,w=(15.63±0.16)mx=(4.72 \pm0.12) \mathrm{m}, {y}=(4.4 \pm 0.2) \mathrm{m}, {w}=(15.63\pm 0.16) \mathrm{m}.
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Correct option: C
9.4±0.89.4 \pm 0.8
Option C (9.4±0.89.4 \pm 0.8) is correct because it accurately calculates the value of z and its associated uncertainty based on the given formula and input values.

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