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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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(aa+x)12+(aa−x)12=\left(\frac{a}{a+x}\right)^{\frac{1}{2}}+\left(\frac{a}{a-x}\right)^{\frac{1}{2}}= ?
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Correct option: A
2+3x24a2+…2+\frac{3 x^2}{4 a^2}+\ldots
Option A (2+3x24a2+…2+\frac{3 x^2}{4 a^2}+\ldots) is correct because expanding both terms using the binomial theorem and adding them together results in the given expression.

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