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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy
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Application +4 | -1
cot⁡  θ=sin⁡  2  θ,  θ≠nπ,  n∈Z\cot \,\,\theta = \sin \,\,2\;\theta ,\,\,\theta \ne n\pi ,\,\,n \in Z, if θ\theta equals
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Correct option: A
45∘45^\circ or 90∘90^\circ
Option A (45∘45^\circ or 90∘90^\circ) is correct because these are the solutions to the equation cot⁡θ=sin⁡2θ\cot \theta = \sin 2\theta within the given constraints.

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