NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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Analyzing +4 | -1

The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?

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Correct option: A

\mathrm{Ce}\left( {\mathrm{At}\mathrm{.}\,\mathrm{No}\mathrm{.}\,\mathrm{58}} \right)

Option A, Ce (Atomic No. 58), is the most likely to deviate easily from the +3 oxidation state because it can also exhibit +4 and +2 oxidation states due to its electronic configuration.

More Questions from REDOX REACTIONS

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The oxidation state of iron in sodium nitroprusside is : Titrations in which liberated

{I_2}

is estimated to carry out the volumetric estimations are known as ….titrations. It is found that V forms a double salt isomorphous with Mohr’s salt. The oxidation number of V in this compound is : For redox reaction,

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

coefficient of reactants in balanced states are

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }

Which one of the following reaction is possible at anode? The couple having oxidised and reduced forms of a substance taking part in an oxidation or reduction half-reaction is called