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JEE PHYSICS MCQ: OSCILLATIONS

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A particle performs simple harmonic motion with amplitude AA. Its speed is tripled at the instant that it is at a distance 23A\frac{2}{3}A from equilibrium position. The new amplitude of the motion is
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Correct option: D
73A\frac{7}{3}A
Option D (73A\frac{7}{3}A) is correct because it's derived from applying the conservation of energy principle in SHM, considering the change in velocity and amplitude.

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