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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
Let f(x)=∫  x2 dx(1+x2)  (1+1+x2)f\left( x \right) = \int \,\,\frac{{{x^2}\,dx}}{{\left( {1 + {x^2}} \right)\,\,\left( {1 + \sqrt {1 + {x^2}} } \right)}} and f(0)=0f\left( 0 \right) = 0. Then, f(1)f\left( 1 \right) is
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Correct option: B
log⁡  (1+2)  −  π4\log \,\,\left( {1 + \sqrt 2 } \right)\,\, - \,\,\frac{\pi }{4}
Option B (log⁡,(1+,2),−,,π4\log \\,\left( {1\\ + \\,\sqrt 2 } \right)\\,\\ - \\,\\,\frac{\pi }{4}) is correct because after solving the integral and applying the given condition f(0)=0f(0) = 0, we find that f(1)=log⁡,(1+,2),−,,π4f(1) = \log \\,\left( {1\\ + \\,\sqrt 2 } \right)\\,\\ - \\,\\,\frac{\pi }{4}.

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