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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Evaluate I=∫01x2−1ln⁡xdx\mathrm{I}=\int_0^1 \frac{\mathrm{x}^2-1}{\ln \mathrm{x}} \mathrm{dx}
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Correct option: C
ln⁡3\ln 3
Option C (ln⁡3\ln 3) is correct because the integral is evaluated using Feynman's trick (differentiation under the integral sign).

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