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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The product 214⋅4116⋅8148⋅161128…2^{\frac{1}{4}} \cdot 4^{\frac{1}{16}} \cdot 8^{\frac{1}{48}} \cdot 16^{\frac{1}{128}} \ldots to ∞\infty is equal to:
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Correct option: A
2122^{\frac{1}{2}}
Option A (2122^{\frac{1}{2}}) is correct because by expressing each term as a power of 2 and summing the exponents, we obtain a G.P. with a sum of 1/2, resulting in 2122^{\frac{1}{2}}.

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