JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

\lim \limits_{{x \rightarrow 1}} \frac{a \sin (x-1)+b \cos (x-1)+4}{x^2-1}=2

, then

(a, b)

is equal to

View answer and explanation

Correct option: D

(4,-4)

Option B (3x+4y-5=0) is correct because the values of a and b obtained from the limit condition satisfy this equation.

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\lim \limits_{{x \rightarrow \infty}} x\left(e^{1 / x}-1\right)

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f^{\prime}(0)

\lim\limits_{n \to \infty } {\left( {1 + \sin \frac{a}{n}} \right)^n}