JEE MATHEMATICS MCQ: INCREASING & DECREASING

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Analyzing +4 | -1

The value of

x

for which

1 + x{\log _e}\left( {x + \sqrt {{x^2} + 1} } \right) \ge \sqrt {{x^2} + 1}

are

View answer and explanation

Correct option: C

x \ge 0

Option C (

x \ge 0

) is correct because the function is increasing for all real numbers, and the inequality holds for

x \ge 0

More Questions from INCREASING & DECREASING

Practice All Chapter MCQs →

f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)