A progressive wave ${\rm{y = a}}\,{\rm{sin}}\left[ {\left( {{\rm{kx}} - {\rm{\omega t}}} \right)} \right]$ is reflected by a rigid wall at ${\rm{x}} = 0$. Then the reflected wave can be represented by

$\begin{array}{*{20}{l}} {{\rm{y = }} - {\rm{asin}}\left( {{\rm{kx + \omega t}}} \right)} \end{array}$

${\rm{y = a}}\,{\rm{sin}}\left( {{\rm{kx + \omega t}}} \right)$

$\begin{array}{*{20}{l}} {{\rm{y = a}}\,{\rm{cos}}\left( {{\rm{kx + \omega t}}} \right)} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{y}} = - {\rm{asin}}\left( {{\rm{kx}} - {\rm{\omega t}}} \right)} \end{array}$

NEET UG PHYSICS MCQ: WAVES

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Understanding +4 | -1

A progressive wave 

\mathrm{y = a}\,\mathrm{sin}\left[ {\left( {\mathrm{kx} - \mathrm{\omega t}} \right)} \right]

is reflected by a rigid wall at

\mathrm{x} = 0

. Then the reflected wave can be represented by

View answer and explanation

Correct option: D

\begin{array}{llllllllllllllllllll} {\mathrm{y = } - \mathrm{asin}\left( {\mathrm{kx + \omega t}} \right)} \end{array}

Option D (

\begin{array}{llllllllllllllllllll}{\mathrm{y = } - \mathrm{asin}\left( {\mathrm{kx + \omega t}} \right)}\end{array}

) is correct because reflection from a rigid wall introduces a phase change of

\pi

, and the wave travels in the opposite direction.

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