JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

\alpha

and

\beta

are roots of

x^2-(\sqrt{1-\cos 2 \theta}) x+\theta=0

, where

0<\theta<\frac{\pi}{2}

. Then,

\lim \limits_{\theta \rightarrow 0^{+}}\left(\frac{1}{\alpha}+\frac{1}{\beta}\right)

View answer and explanation

Correct option: C

\sqrt{2}

The correct answer is C (

\sqrt{2}

) because by simplifying the expression and using the limit definition, the value can be determined as

\sqrt{2}

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\lim \limits_{{x \rightarrow \infty}} x\left(e^{1 / x}-1\right)

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