JEE MATHEMATICS MCQ: LIMITS

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f(x)=\left\{\begin{array}{rr}x \sin \frac{1}{x}, & x \neq 0 \\ 0, & x=0\end{array}\right.

, then

\lim \limits_{{x \rightarrow 0}} f(x)=

View answer and explanation

Correct option: B

Option B (0) is correct because the limit of the function as x approaches 0 is 0, as shown by the Squeeze Theorem.

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