NEET UG PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

1 Easy

1 of 1

Application +4 | -1

A wire of cross sectional area

4\,m{m^2}

is fixed between two points at

{30^ \circ }C.Y = 2 \times {10^{11}}pa

and

\alpha = {10^{ - 5}}/\,{\,^ \circ }C

; When the temperature falls to

{20^ \circ }C

, the tension in the string in (newton) is

View answer and explanation

Correct option: C

Option C (80) is correct because it is the tension calculated using Young's modulus, area, coefficient of linear expansion and change in temperature.

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60 \mathrm{~cm} \times 50 \mathrm{~cm} \times 20 \mathrm{~cm}

1 \mathrm{~cm}

0^{\circ} \mathrm{C}

40^{\circ} \mathrm{C}

3.4 \times 10^5 \mathrm{~J} \mathrm{~kg}^{-1}

\left. {0.05{\text{W}}{{\text{m}}^{ - 1}}^\circ {{\text{C}}^{ - 1}}} \right)

2 \times 10^5 \mathrm{~J} / \mathrm{sm}^2

127^{\circ} \mathrm{C}

32 \times 10^5 \mathrm{~J} / \mathrm{s}-\mathrm{m}^2

\sigma

+ \frac{1}{2}