JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Application +4 | -1

a_{1}, a_{2}, a_{3}, \ldots, a_{n}

are in HP, then

a_{1} a_{2}+a_{2} a_{3}+\cdots+a_{n-1} a_{n}

will be equal to

View answer and explanation

Correct option: C

(n-1) a_{1} a_{n}

Option C (

(n-1) a_{1} a_{n}

) is correct because it is derived by summing the differences of reciprocals in the corresponding AP.

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