Question

The focal length of a mirror is given by $\frac{1}{f} = \frac{1}{u} + \frac{{1\;}}{v}$ where u and $v$ represent object and image distances respectively. The maximum relative error in $f$ is

Accepted Answer

$\frac{{\Delta f}}{f} = \frac{{\Delta u}}{u} + \frac{{\Delta v}}{v} + \frac{{\Delta u}}{{u + v}} + \frac{{\Delta v}}{{u + v}}$

Answer

$\frac{{\Delta f}}{f} = \frac{{\Delta u}}{u} + \frac{{\Delta v}}{v}$

Answer

$\frac{{\Delta f}}{f} = \frac{1}{{\Delta u/u}} + \frac{1}{{\Delta v/v}}$

Answer

$\frac{{\Delta f}}{f} = \frac{{\Delta u}}{u} + \frac{{\Delta v}}{v} - \frac{{\Delta \left( {u + v} \right)}}{{u + v}}$

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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