If $f\left( x \right) = {\cos ^2}x + {\sec ^2}x$, then

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

f\left( x \right) = {\cos ^2}x + {\sec ^2}x

, then

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Correct option: D

f\left( x \right) \ge 2

Option D is correct because the minimum value of cos²x + sec²x is 2, which is achieved when cos²x = 1.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

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y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

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A P

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G P

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\frac{3}{4}