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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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The sum of the series sin⁡θsec⁡3θ+sin⁡3θsec⁡32θ+sin⁡32θsec⁡33θ\sin \theta \sec 3 \theta+\sin 3 \theta \sec 3^2 \theta+\sin 3^2 \theta \sec 3^3 \theta +…n+\ldots n terms, is
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Correct option: C
12[tan⁡3nθ−tan⁡θ]\frac{1}{2}\left[\tan 3^n \theta-\tan \theta\right]
Option C, 12[tan⁡3nθ−tan⁡θ]\frac{1}{2}\left[\tan 3^n \theta-\tan \theta\right], is correct because the series telescopes, leaving only the first and last terms after simplification.

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