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JEE PHYSICS MCQ: GRAVITATION

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A satellite is orbiting just above the surface of the earth with period TT. If dd is the density of the earth and GG is the universal constant of gravitation, the quantity 3πGd\frac{3 \pi}{G d} represents
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Correct option: D
T2T^2
Option D (T2T^2) is correct because the quantity 3πGd\frac{{3 \pi}}{{G d}} is equal to the square of the orbital period TT of a satellite orbiting just above the Earth's surface.

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