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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Application +4 | -1
The value of lim⁡x→1log⁡xsin⁡πx\lim \limits_{{x \rightarrow 1}} \frac{\log x}{\sin \pi x}, is
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Correct option: D
−1π-\frac{1}{\pi}
Option D (−1π-\frac{1}{\pi}) is correct because the limit can be evaluated using the standard limit lim⁡x→0sin⁡xx=1\lim_{x \to 0} \frac{\sin x}{x} = 1 and lim⁡x→1ln⁡xx−1=1\lim_{x \to 1} \frac{\ln x}{x-1} = 1.

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