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JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1
What will be dimensions of aa in the formula p=(p0+a)(b+t)p=\left(p_0+a\right)(b+t) here p=p= pressure, t=t= time, and x=x= distance:
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Correct option: A
[ML−1T−3]\left[\mathrm{ML}^{-1} \mathrm{T}^{-3}\right]
Option A ([ML-1 T-3]) is correct because, based on dimensional analysis, the dimensions of 'a' in the given formula are [ML-1 T-3].

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