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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
lim⁡x→01+sin⁡2x3−1−2tan⁡x4sin⁡x+tan⁡2x\lim \limits_{{x \rightarrow 0}} \frac{\sqrt[3]{1+\sin ^2 x}-\sqrt[4]{1-2 \tan x}}{\sin x+\tan ^2 x} is equal to
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Correct option: C
12\frac{1}{2}
Option C (12\frac{{1}}{{2}}) is correct because using approximations for small x, the limit simplifies to 12\frac{{1}}{{2}}.

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