JEE PHYSICS MCQ: MAGNETISM AND MATTER

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An electron in an atom revolves around the nucleus in an orbit of radius 0.5 Å. Calculate the equivalent magnetic moment if the frequency of revolution of the electron is

10^{10}\,\mathrm{MHz}

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Correct option: A

1.256 \times 10^{-23} \mathrm{Am}^2

Option A (

1.256 \times 10^{-23} \mathrm{Am}^2

) is correct because the magnetic moment is calculated using the current due to the electron's revolution and the area of the orbit.

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Curie temperature is the one above which A vibration magnetometer consists of two identical bar magnets placed one over the other such that they are perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is

{2^{5/4}}

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\mu_{\mathrm{d}}, \mu_{\mathrm{p}}

and

\mu_{\mathrm{f}}

respectively, then :- Which of the following is most suitable for the core of electromagnets