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JEE MATHEMATICS MCQ: SCALAR TRIPLE PRODUCT

1 Easy
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Application +4 | -1
Let a⃗,  b⃗   and    c⃗\mathbf{\vec a},\,\,\mathbf{\vec b}\,\mathrm{\;and\;}\,\,\mathbf{\vec c} be three non-coplanar vectors and let p⃗,  q⃗     and   r⃗\mathbf{\vec p},\,\,\mathbf{\vec q}\mathrm{\;}\,\,\,\mathrm{and}\,\mathrm{\;}\mathbf{\vec r} be vector defined by the relations. p⃗=b⃗×c⃗[  a⃗   b⃗   c⃗  ],  q⃗=c⃗×a⃗[a⃗   b⃗   c⃗  ]  and    r⃗=a⃗×b⃗[a⃗   b⃗   c⃗  ]\mathbf{\vec p} = \frac{{\mathbf{\vec b} \times \mathbf{\vec c}}}{{\left[ {\;\mathbf{\vec a}\,\;\mathbf{\vec b}\,\;\mathbf{\vec c}\;} \right]}},\,\,\mathbf{\vec q} = \frac{{\mathbf{\vec c} \times \mathbf{\vec a}}}{{\left[ {\mathbf{\vec a}\;\,\mathbf{\vec b}\;\,\mathbf{\vec c}\;} \right]}}\,\,\mathrm{and\;}\,\,\mathbf{\vec r} = \frac{{\mathbf{\vec a} \times \mathbf{\vec b}}}{{\left[ {\mathbf{\vec a}\;\,\mathbf{\vec b}\;\,\mathbf{\vec c}\;} \right]}}. Then, the value of the expression (a⃗+b⃗)  ⋅  p⃗+(b⃗+c⃗)  ⋅  q⃗+(c⃗+a⃗)  ⋅  r⃗\left( {\mathbf{\vec a} + \mathbf{\vec b}} \right)\,\, \cdot \,\,\mathbf{\vec p} + \left( {\mathbf{\vec b} + \mathbf{\vec c}} \right)\,\, \cdot \,\,\mathbf{\vec q} + \left( {\mathbf{\vec c} + \mathbf{\vec a}} \right)\,\, \cdot \,\,\mathbf{\vec r} is equal to
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Correct option: D
3
Option D (3) is correct because by using the properties of reciprocal vectors, we can simplify the expression to equal 3.

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If r⃗⋅a⃗=r⃗⋅b⃗=r⃗⋅c⃗=0\vec r\cdot\vec a = \vec r\cdot\vec b = \vec r\cdot\vec c = 0 for some non-zero vector r⃗,\vec r, then the value of [a⃗b⃗c⃗],\left[ {\vec a\vec b\vec c} \right], is The shortest distance between the lines x−32=y−23=z−1−1\frac{{x - 3}}{2} = \frac{{y - 2}}{3} = \frac{{z - 1}}{{ - 1}} and x+32=y−61=z−53,\frac{{x + 3}}{2} = \frac{{y - 6}}{1} = \frac{{z - 5}}{3}, is Let \mathbf{\vec a} = \widehat \mathbf{i} - \mathbf{\hat k},\;\mathbf{\vec b} = x\widehat \mathbf{i} + \widehat \mathbf{j} + \left( {1 - x} \right)\mathbf{\hat k}\mathbf{\vec a} = \widehat \mathbf{i} - \mathbf{\hat k},\;\mathbf{\vec b} = x\widehat \mathbf{i} + \widehat \mathbf{j} + \left( {1 - x} \right)\mathbf{\hat k} and \mathbf{\vec c} = y\widehat \mathbf{i} + x\widehat \mathbf{j} + \left( {1 + x - y} \right)\mathbf{\hat k}.\mathbf{\vec c} = y\widehat \mathbf{i} + x\widehat \mathbf{j} + \left( {1 + x - y} \right)\mathbf{\hat k}. Then [a⃗,  b⃗,  c⃗]\left[ {\mathbf{\vec a},\;\mathbf{\vec b},\;\mathbf{\vec c}} \right] depends on If a⃗,b⃗\vec{a}, \vec{b} are non-zero vectors, then ((a⃗×b⃗)×a⃗)⋅((b⃗×a⃗)×b⃗)((\vec{a} \times \vec{b}) \times \vec{a}) \cdot((\vec{b} \times \vec{a}) \times \vec{b}) equals a⋅(a×b)=a \cdot(a \times b)= The length of the perpendicular from the origin to the plane passing through the point a and containing the line r=b+λc\mathbf{r}=\mathbf{b}+\lambda \mathbf{c} is
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