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JEE PHYSICS MCQ: OSCILLATIONS

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The function (

\sin \omega t-\cos \omega t)

represents the S.H.M having a time period

T

View answer and explanation

Correct option: B

2 \pi / \omega

Option B (

2 \pi / \omega

) is correct because the time period of a simple harmonic motion is given by

T = 2 \pi / \omega

.

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{y_2}

its potential energy is

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\left( {{y_1} + {y_2}} \right)